In the adjoining circuit diagram, the readings of ammeter and voltmeter are $2\, A$ and $120 \,V$, respectively. If the value of $R$ is $75\, \Omega$, then the voltmeter resistance will be $\Omega$
AIIMS 2018, Medium
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1A moving coil galvanometer allows a full scale current of $10^{-4}\, A$. A series resistance of $2\, M\,\Omega $ is required to convert the above galvanometer into a voltmeter of range $0 -5\, V$. Therefore the value of shunt resistance required to convert the above galvanometer into a ammeter of range $0-10\, mA$ is....$\Omega $View Solution
- 2View SolutionA negative test charge is moving near a long straight wire carrying a current. The force acting on the test charge is parallel to the direction of the current. The motion of the charge is
- 3A circular coil of $1000\,turns$ and area of cross-section $1.5 \times 10^{-4}\, m^2$, is carrying a current of $2\,A$. What is the magnetic moment associated with the coil?....$Am^2$View Solution
- 4A voltmeter of resistance $20000\,\Omega$ reads $5$ volt. To make it read $20$ volt, the extra resistance required isView Solution
- 5A galvanometer of resistance $100\,\Omega $ has $50\, divisions$ on its scale and has sensitivity of $20\,\mu A / division$. It is to be converted to a voltmeter with three ranges, of $0-2\, V$, $0-10\, V$ and $0-20\, V$. The appropriate circuit to do so isView Solution
- 6A particle having a mass of $10^{- 2} \,kg$ carries a charge of $5 \times 10^{-8}\, C.$ The particle is given an initial horizontal velocity of $10^5\, m/s $ in the presence of electric field $E$ and magnetic field $B.$ To keep the particle moving in a horizontal direction, it is necessary thatView Solution
$(1)$ $\vec B$ should be perpendicular to the direction of velocity and $\vec E$ should be along the direction of velocity$(2)$ Both $\vec B$ and $\vec E$ should be along the direction of velocity$(3)$ Both $\vec B$ and $\vec E$ are mutually perpendicular and perpendicular to the direction of velocity.$(4)$ $\vec B$ should be along the direction of velocity and $\vec E$ should be perpendicular to the direction of velocityWhich one of the following pairs of statements is possible? - 7An electric current passes through a long straight wire. At a distance $5\, cm$ from the wire, The magnetic field is $B$. The field at $20\, cm$ from the wire would beView Solution
- 8$AB$ and $CD$ are smooth parallel rails, separated by a distance $l$, and inclined to the horizontal at an angle $\theta$ . $A$ uniform magnetic field of magnitude $B$, directed vertically upwards, exists in the region. $EF$ is a conductor of mass $m$, carrying a current $i$, if $B$ is normal to the plane of the railsView Solution
- 9Two moving coil meters $M_1$ and $M_2$ having the following particulars :-View Solution
$R_1 = 10\,\Omega , N_1 = 30, A_1 = 3.6\times10^{-3}\, m^2, B_1 = 0.25\, T$
$R_2 = 14\,\Omega , N_2 = 42, A_2 = 1.8\times10^{-3}\, m^2, B_2 = 0.50\, T$
(The spring constants are identical for the two meters). Determine the ratio of voltage sensitivity of $M_2$ and $M_1$ - 10In figure the cube is of $40\,\, cm$ edge. Four straight segment of wire $ab, bc, cd$ and $da$ form a closed loop that carries a current $I = 5\,A$. A uniform magnetic field $0.02\,\,T$ is in $+y\,-$ direction ratio of magnetic force on segement $ab$ and $bc$ isView Solution
