An aromatic compound 'A ’ on treatment with CHCl_3/ KOH gives two… - Vidyadip

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An aromatic compound $'A\ ’$ on treatment with $\ce{CHCl_3/ KOH}$ gives two compounds $'B\ ’$ and $'C\ ’.$ Both $B$ and $C$ give the same product $'D\ ’$ when distilled with zinc dust. Oxidation of $D$ gives $E$ having molecular formula $\ce{C_7H_6O_2}.$ The sodium salt of $E$ on heating with sodalime gives $F$ which may also be obtained by distilling $A$ with zinc dust. Identify $A$ to $F.$

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