An electric dipole moment $\vec p = (2.0\hat i + 3.0\hat j)$ $\mu C. $ $m$ is placed in a uniform electric field $\vec E = (3.0\hat i + 2.0\hat k)$ $×$$10^5$ $N$ $C^{-1}$.
Diffcult
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Torque $\tau=\vec{P} \times \vec{E}=(2.0 \hat{\imath}+3.0 \hat{j}) 10^{-6} \times(3 \hat{i}+2 \hat{k}) 10^{5}=-0.9 \hat{k}-0.4 \hat{j}+0.6 \hat{i}$
Potential energy $|U|=|-\vec{P} . \vec{E}|=0.6 \mathrm{J}$
If the dipole is rotated in field direction so for maximum potential
$U_{\max }=|\vec{P}||\vec{E}| \cos 0=\sqrt{2^{2}+3^{2}} \times 10^{-6} \times \sqrt{3^{2}+2^{2}} \times 10^{5}=1.3 \mathrm{J}$
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