An electric heater consists of a nichrome coil and runs under $220 \,V$, consuming $1 \,kW$ power. Part of its coil burned out and it was reconnected after cutting off the burnt portion.The power it will cunsume now is
KVPY 2010, Medium
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(a)
Power $P=\frac{V^2}{R}$ as $V$ remains constant in given condition, while current changes as resistance is reduced.
Power consumed by heater coil $P \propto \frac{1}{R}$.
On cutting part of coil, its resistance decreases. So, power consumed by coil increases and it will be more than $1 \,kW$.
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