An electric heater of resistance $6 \,ohm$ is run for $10$ minutes on a $120\, volt$ line. The energy liberated in this period of time is
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(b) $H = {i^2}Rt = \frac{{{V^2}t}}{R} = \frac{{120 \times 120 \times (10 \times 60)}}{6}$$ = 14.4 \times {10^5}joule$
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