An electric heater supplies heat to a system at a rate of $100\;W.$ If system performs work at a rate of $75$ Joules per second. At what rate (in $J/s$) is the internal energy increasing?
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Heat is supplied to the system at a rate of $100 W$

Heat supplied, $Q=100 J / s$

The system performs at a rate of $75 J / s$

Work done, $W=75 J / s$

From the first law of thermodynamics, we have

$Q=U+W$

Where, $U=$ Internal energy

$\therefore U= Q -W$

$=100-75$

$=25 J / s$

$=25 W$

Therefore, the internal energy of the given electric heater increases at a rate of $25\; W$

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