An electric lift with a maximum load of 2000 ,kg (lift+ passenger… - Vidyadip

MCQ

An electric lift with a maximum load of $2000\,kg$ (lift+ passengers) is moving up with a constant speed of $1.5\,ms ^{-1}$. The frictional force opposing the motion is $3000\,N$. The minimum power delivered by the motor to the lift in watts is: $\left(g=10\,ms^{-2}\right)$

A
$20000$
✓
$34500$
C
$23500$
D
$23000$

✓

Answer

Correct option: B.

$34500$

b
Constant velocity $\Rightarrow a =0$

$\Rightarrow T = W + f$

$=20000+3000$

$=23000\,N$

$\text { Power } = Tv$

$=23000 \times 1.5$

$=34500 \text { watts }$

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