$\lambda = \frac{h}{p}$ or $\lambda = \frac{h}{{mv}} \Rightarrow eV = \frac{1}{2}m{v^2}$ or $\nu = \sqrt {\frac{{2eV}}{m}} $
$\lambda = \frac{h}{{\sqrt {2meV} }}$$ = \frac{{6.62 \times {{10}^{ - 34}}}}{{\sqrt {2 \times 9.1 \times {{10}^{ - 31}} \times 2.8 \times {{10}^{ - 23}}} }}$
$\lambda = 9.28 \times {10^{ - 8}}\,meter$.
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The temperature at which $K _{ C }=20.4$ and $K _{ P }=600.1,$ is ....... $K$. (Round off to the Nearest Integer).
[Assume all gases are ideal and $R =0.0831\, L\,bar \, K ^{-1} mol ^{-1}]$
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