An electron with kinetic energy $K _{1}$ enters between parallel plates of a capacitor at an angle $'\alpha'$ with the plates. It leaves the plates at angle $' \beta '$ with kinetic energy $K _{2}$. Then the ratio of kinetic energies $K _{1}: K _{2}$ will be ....... .
JEE MAIN 2021, Diffcult
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velocity along the plate will not change.
$\therefore v _{1} \cos \alpha= v _{2} \cos \beta$
$\frac{ K _{1}}{ K _{2}} \Rightarrow \frac{ v _{1}^{2}}{ v _{2}^{2}}=\frac{\cos ^{2} \beta}{\cos ^{2} \alpha}$
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