Question
An element A and B constitute bcc type crystalline structure. Element A occupies body centre position and B is at the corners of cube. What is the formula of the compound? What are the coordination numbers of A and B ?

Answer

Given : Crystalline structure is bcc type.
Atoms $A$ are at 8 comers and atom $B$ is at body centre.
$\therefore$ Number of atoms of $A$ in a unit cell
$=\frac{1}{8} \times 8=1 \text {. }$
Number of atom $B$ in a unit cell $=1$.
Since unit cell contains one atom each of $A$ and $B$, the formula of the compound is $A B$.
The coordination number of an atom $A$ at comer is 8 .
The coordination number of an atom $B$ at body centre is 8 .
Answer. Formula of the compound $= AB$.
Coordination number of $A=8$
Coordination number of $B=8$.

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