An enclosed ideal gas is taken through a cycle as shown in the figure. Then
AAlong $AB$, temperature decreases while along $BC$ temperature increases
BAlong $AB$, temperature increases while along $BC$ the temperature decreases.
CAlong $CA$ work is done by the gas and the internal energy remains constant.
DAlong $CA$ work is done on the gas and internal energy of the gas increases.
Diffcult
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AAlong $AB$, temperature decreases while along $BC$ temperature increases
a For ideal gas, $P=n R T \frac{1}{V}$
Along $AB$, $P$ is constant and $\frac{1}{V}$ increases $\Longrightarrow T$ decreases
Along $BC,$ $P$ increases and $\frac{1}{V}$ remains constant $\Longrightarrow T$ increases
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