An erect image 2.0cm high is formed 12cm from a lens, the object being 0.5cm high. Find the focal length of the lens.
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$h_2$ = 2cm (Erect image) v = 12cm $h_1$ = 0.5cm$\text{m}=\frac{\text{v}}{\text{u}}=\frac{\text{h}_2}{\text{h}_1}$
$\frac{-12}{\text{u}}=\frac{2}{0.5}$
$\text{u}=-3\text{cm}$
Lens formula, $\frac{1}{\text{v}}-\frac{1}{\text{u}}=\frac{1}{\text{f}}$$\frac{1}{-12}-\frac{1}{-3}=\frac{1}{\text{f}}$
$\frac{-1+4}{12}=\frac{1}{\text{f}}$
$\text{f}=4\text{cm}$
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