An ideal battery of 4, V and resistance R are connected in series in the primary circuit of a potentiometer of length 1, m and

Q: An ideal battery of $4\, V$ and resistance $R$ are connected in series in the primary circuit of a potentiometer of length $1\, m$ and resistance $5\,\Omega $ . The value of $R$, to give a difference of $5\, mV$ across $10\, cm$ of potentiometer wire, is: ................ $\Omega$

c $i=\frac{4}{5+R}$ $V_{A B}=i(5)=\frac{20}{5+R}$ $V_{A P}=\frac{V_{A B}}{L}(0.1)=\frac{20}{5+R}\left(\frac{0.1}{1}\right)=\frac{2}{5+R}$ Now, $\frac{2}{5+R}=5 \times 10^{-3}$ $\Rightarrow \quad R=395\, \Omega$

SECTION - A [PHYSICS MCQ]

GSEB - English Medium

An ideal battery of $4\, V$ and resistance $R$ are connected in series in the primary circuit of a potentiometer of length $1\, m$ and resistance $5\,\Omega $ . The value of $R$, to give a difference of $5\, mV$ across $10\, cm$ of potentiometer wire, is: ................ $\Omega$

A$490$
B$480$
C$395$
D$495$

JEE MAIN 2019, Medium

STD 11 Science
JEE
STD 12 - 3. current electricity
Physics

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