a
Consider the expression,
$\frac{P_{1} V_{1}}{T_{1}}=\frac{P_{2} V_{2}}{T_{2}}$
Substitute 1 bar for $P_{1}, 30 m ^{3}$ for $V_{1}, 320 K$ for $T_{1}, 10 m ^{3}$ for $V_{2}$ and $280 K$ for $T_{2}$ in above relation.
$\frac{1(30)}{320}=\frac{P_{2}(10)}{280}$
$P_{2}=2.625 bar$