MCQ
An ideal gas is subjected to a thermodynamic process $PV^{2.5} = 0.40$ where $P$ is in $Pa$ and $V$ is in $m^3$.What is the slope of the $P-V$ curve with volume plotted against $x-$ axis at $V=1\, m^3$ ?
  • $-1$
  • B
    $-3.5$
  • C
    $-2.5$
  • D
    None of these

Answer

Correct option: A.
$-1$
a
$\mathrm{PV}^{2.5}=0.40$

$\mathrm{P}=0.40 \mathrm{V}^{-2.5}$

$\frac{\mathrm{dP}}{\mathrm{dV}}=0.40\left[-2.5 \mathrm{V}^{-3.5}\right]$

at $\quad V=1$

$\left(\frac{\mathrm{dP}}{\mathrm{dV}}\right)_{\mathrm{V}=1}=-1$

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