An ideal gas is trapped inside a test tube of cross-sectional area $20 \times 10^{-6} \,\,m^2$ as shown in the figure. The gas occupies a height $L_1$ at the bottom of the tube and is separated from air at atmospheric pressure by a mercury column of mass $0.002\,\, kg$. If the tube is quickly turned isothermally, upside down so that $L_2$ mercury column encloses the gas from below. The gas now occupies height $L_1$ in the tube. The ratio $L_1$ is [Take atmospheric pressure $= 10^5 Nm^{-2}]$
A$\frac{{102}}{{101}}$
B$\frac{{101}}{{99}}$
C$\frac{{99}}{{100}}$
D$\frac{{100}}{{99}}$
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B$\frac{{101}}{{99}}$
b $\frac{L_{2}}{L_{1}}=\frac{P_{0} A+M g}{P_{0} A-M g}$
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