d
We have two types of charges $-e$ and $+ 2 e$
When a potential different is applied both the charges drift in opposite directions.
$\therefore \mathrm{i}=\mathrm{neV}_{\mathrm{d} \mathrm{A}}$
$i_{(+v e)}=(n)(2 e) \frac{\left(V_{d}\right)}{4} A=\frac{n e V_{d} A}{2}$
$\mathrm{i}_{(-\mathrm{e})}=\mathrm{n}(-\mathrm{e})\left(-\mathrm{V}_{\mathrm{d}}\right), \mathrm{A}=\mathrm{n}_{\mathrm{e}} \mathrm{V}_{\mathrm{d}} \mathrm{A}$
$i_{total}$ $=i+2 e+i-e$
$i=\frac{3}{2} n e V_{d} A$