An object is placed at a distance of 12cm in front of a concave mirror of radius of curvature 30cm. List four characteristics of the image formed by the mirror.
CBSE DELHI - SET 3 2017
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Here u = -20cm, f = +15cm, v = ? Using mirror formula, we have,$\frac{1}{\text{v}}+\frac{1}{\text{u}}=\frac{1}{\text{f}}$
$\frac{1}{\text{v}}-\frac{1}{20}=\frac{1}{15}$
$\frac{1}{\text{v}}=\frac{1}{15}+\frac{1}{20}$
$\frac{1}{\text{v}}=\frac{4+3}{60}$
$\text{v}=\frac{60}{7}=8.5\text{cm}$
Therefore, the image formed behind the mirror and forms virtual, erect, diminished, image.
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A student focuses the image of a well illuminated distant object on a screen using a convex lens. After that he gradually moves the object towards the lens and each time focuses its image on the screen by adjusting the lens.
In which direction-towards the screen or away from the screen, does he move the lens?
What happens to the size of the image-does it decrease or increase?
What happens to the image on the screen when he moves the object very close to the lens?
An object is placed at a distance of 30cm in front of a convex mirror of focal length 15cm. Write four characteristics of the image formed by the mirror.
With the help of a ray diagram, determine the position, nature and size of the image formed of an object placed at the centre of curvature of a concave mirror.
Draw a ray diagram to show the formation of a virtual magnified image of an object by a convex lens. In your diagram, the position of object and image with respect to the principal focus should be shown clearly.