Question
An object is placed (i) asymmetrically (ii) symmetrically, between two plane mirrors inclined at an angle of $50^\circ $. Find the number of images formed.
✓
Answer
Angle between the mirrors, $\theta=50^{\circ}$
Now, $n =360^{\circ} / \theta^{\circ}=360^{\circ} / 50^{\circ}=7.27$, which is odd.
(i) When placed asymmetrically, number of images formed will be $n$, i.e.$ 7 .$
(ii) When placed symmetrically, number of images formed will be $(n-1)$; i.e. $7-1=6$ images
Now, $n =360^{\circ} / \theta^{\circ}=360^{\circ} / 50^{\circ}=7.27$, which is odd.
(i) When placed asymmetrically, number of images formed will be $n$, i.e.$ 7 .$
(ii) When placed symmetrically, number of images formed will be $(n-1)$; i.e. $7-1=6$ images
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