An open pipe of length $33\,cm$ resonates to a frequency of $1000\,Hz$ . The mode of vibration is: (velocity of sound $= 330\,m/s$ )
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As $\frac{V}{2 l}=\frac{330 \times 100}{2 \times 33}=500 H z$

In second harmonic frequency $=\frac{V}{l}=1000 H z$

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