An organ pipe $40\,cm$ long is open at both ends. The speed of sound in air is $360\,ms ^{-1}$. The frequency of the second harmonic is $...........\,Hz$.
JEE MAIN 2023, Easy
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For second harmonic of open organ pipe
$L =\lambda$
So frequency of vibration is $f =\frac{ V }{\lambda}$
$f =\frac{ V }{\lambda}=\frac{ V }{ L }=\frac{360}{\frac{40}{100}}=900\,Hz$
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