Question
An organic compound $'A\ ' ($molecular formula $C_3H_6O)$ is resistant to oxidation but forms a compound $'B\ ' (C_3H_8O)$ on reduction. $'B\ '$ reacts with $HBr$ to form a bromide $'C\ '$ which on treatment with alcoholic $KOH$ forms an alkene $'D\ ' (C_3H_6).$ Deduce the structures of $A, B, C$ and $D.$
