MCQ
An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave $C, 38.71\%$ and $H, 9.67\%.$ The empirical formula of the compound would be
- A$CHO$
- B$CH_4O$
- ✓$CH_3O$
- D$CH_2O$
✓
Answer
Correct option: C.
$CH_3O$
c
$C \quad 38.71 \quad 12 \quad 38.71 / 12 \quad 3.22 / 3.22=1$
$C \quad 38.71 \quad 12 \quad 38.71 / 12 \quad 3.22 / 3.22=1$
$H \quad 9.67 \quad \;\;1 \;\;\quad 9.67 / 1 \;\;\quad 9.67 / 3.22=3$
$O\quad 51 .62\quad 16\quad 51.62 / 16\quad 3.22 / 3.22=1$
Hence the empirical formula of the compound would be $C H_{3} O$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The molecular formula of chloride of a metal $M$ is $MC{l_3}.$ The formula of its carbonate would be
→${C_6}{H_6}\mathop {\xrightarrow{{C{H_3}COCl}}}\limits_{AlC{l_3}} A\mathop {\xrightarrow{{Zn - Hg}}}\limits_{HCl} B$
→The end product in the above sequence is :
Identify the product $(C)$ in the following series of reaction
→In which species, $X-O$ bond order is $1.5$ and contains $p \pi - d \pi$ bond $(s).$
→The total number of lone pairs of electrons on oxygen atoms of ozone is $...........$.
→Given below are two statements:
→Statement $(I)$ : Both metal and non-metal exist in $\mathrm{p}$ and $d$-block elements.
Statement $(II)$ : Non-metals have higher ionisation enthalpy and higher electronegativity than the metals.
In the light of the above statements, choose the most appropriate answer from the option given below:
Which of the following reaction teakes place at anode?
According to Aufbau principle, the electron has a tendency to occupy that sub $-$ shell which has :
→For the given reaction :
$H_2(g) + S(s) \to H_2S(g)$ ; $\Delta {H_r} = 100\, kJ/mol$ and $\Delta {S_r} = 400\, J/mol/K$ Temperature at which above reaction occurs reversibly is (Assumning $\Delta {H_r}$ and $\Delta {S_r}$ are independent of temperature).....$K$
→$H_2(g) + S(s) \to H_2S(g)$ ; $\Delta {H_r} = 100\, kJ/mol$ and $\Delta {S_r} = 400\, J/mol/K$ Temperature at which above reaction occurs reversibly is (Assumning $\Delta {H_r}$ and $\Delta {S_r}$ are independent of temperature).....$K$
The relation between change in internal energy $(\Delta E)$, change in enthalpy $(\Delta H)$ and work done $ (W)$ is represented as
→