An unknown chlorohydrocarbon has 3.55 % of chlorine. If each mole… - Vidyadip

MCQ

An unknown chlorohydrocarbon has $3.55\%$ of chlorine. If each molecule of the hydrocarbon has one chlorine atom only, chlorine atoms present in $1\,g$ of chlorohydrocarbon are (Atomic wt. of $Cl = 35.5\,u;$ Avogadro constant $= 6.023 \times 10^{23}\,mol^{- 1}$ )

A
$6.023 \times {10^9}$
B
$6.023 \times {10^{23}}$
C
$6.023 \times {10^{21}}$
✓
$6.023 \times {10^{20}}$

✓

Answer

Correct option: D.

$6.023 \times {10^{20}}$

d
Given percentage of chlorine in an hydrocarbon $= 3.55\%$ i,e.,

$100\,g$ of chlorohydrocarbon has $3.55\,g$ of chlorine.

$1\,g$ of chlorohydrocarbon will have $\frac{{3.55}}{{100}} = 0.0355\,g$ of chlorine.

Atomic wt. of $Cl = 35.5\,g/mol$

Number of moles of $Cl$ $ = \frac{{0.0355\,g}}{{35.5\,g/mol}} = 0.001$ $mole$

Number of atoms of $Cl = 0.001\,mole$ $\times 6.023 \times 10^{23}\,mol^{-1}$

$= 6.023 \times 10^{20}$

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