Question
✓
Answer
(a) Numbers 1 to 12 are written along the circumference of a clock at equal distances. 360 ÷ 12 = 30.
Hence, angle between two consecutive numbers is $30^{\circ}$
At $1^{\circ \prime}$ clock hands are at 0 and 1 (consecutive numbers)
Hence angle between them is $30^{\circ}$.
(b) Angle between hands at $2 o^{\circ}$ clock $=2 \times 30^{\circ}=60^{\circ}$ angle between hands at 4 o $^{\prime}$ clock $=4 \times 30^{\circ}=120^{\circ}$
Angle between hands at $6 o^{\prime}$ clock $=6 \times 30^{\circ}=180^{\circ}$
(c) Angle between hands at $5o^{\prime}$ clock $=5 \times 30^{\circ}=150^{\circ}$
Angle between hands at $7 o^{\prime}$ clock $=7 \times 30^{\circ}=210^{\circ}$
Angle between hands at $8 o^{\prime}$ clock $=8 \times 30^{\circ}=240^{\circ}$
Hence, angle between two consecutive numbers is $30^{\circ}$
At $1^{\circ \prime}$ clock hands are at 0 and 1 (consecutive numbers)
Hence angle between them is $30^{\circ}$.
(b) Angle between hands at $2 o^{\circ}$ clock $=2 \times 30^{\circ}=60^{\circ}$ angle between hands at 4 o $^{\prime}$ clock $=4 \times 30^{\circ}=120^{\circ}$
Angle between hands at $6 o^{\prime}$ clock $=6 \times 30^{\circ}=180^{\circ}$
(c) Angle between hands at $5o^{\prime}$ clock $=5 \times 30^{\circ}=150^{\circ}$
Angle between hands at $7 o^{\prime}$ clock $=7 \times 30^{\circ}=210^{\circ}$
Angle between hands at $8 o^{\prime}$ clock $=8 \times 30^{\circ}=240^{\circ}$
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