MCQ
Angular momentum and angular velocity for a rolling sphere of radius $R$ are related by the formula:
  • $\text{L}=\text{I}\omega:\text{I}$ is the moment of inertia of the sphere.
  • B
    $\text{L}=\text{I}\omega^2\text{I}$ is the moment of inertia of the sphere.
  • C
    $\text{L}=\frac{\text{I}}{\omega},\text{I}$ is the moment of inertia of the sphere.
  • D
    $\text{L}=\text{I}\omega−\text{f}×\text{R};\text{f}$ is the frictional force and $R$ is the radius of the sphere and $I$ is the moment of inertia of the sphere.

Answer

Correct option: A.
$\text{L}=\text{I}\omega:\text{I}$ is the moment of inertia of the sphere.
Angular momentum is related to angular velocity using $\text{L}=\text{I}\omega:\text{I}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Figures below show water flowing through a horizontal pipe from left to right. Note that the pipe in the middle is narrower. Choose the most appropriate depiction of water levels in the vertical pipes.
A $U-$ tube is such that the diameter of one limb is $0.4\,mm$ and that of other is $d\, mm$ . If the surface tension of water contained in the tube is $0.07\,N/m$ and the difference in the levels of liquid in the limbs is $3.6\,cm,$ then the value of $d$ is
A particle is moving in a circular path of radius a under the action of an attractive potential $U = - \frac{k}{{2{r^2}}}$ Its total energy is
Two planets $A$ and $B$ have same mass and radii $(R)$ . The variation of density of the planets with distance from centre is shown in the following diagrams. The ratio of acceleration due to gravity at the surface of the planets $A$ and $B$ will be
An aeroplane moving horizontally with a speed of $180\, km/hr$. drops a food packet while flying at a height of $490\,m$. The horizontal range is........$m$
In order to double the frequency of the fundamental note emitted by a stretched string, the length is reduced to $\frac{3}{4}$$^{th}$ of the original length and the tension is changed. The factor by which the tension is to be changed, is
A reference frame attached to the earth:
  1. Is an inertial frame by definition.
  2. Cannot be an inertial frame because the earth is revolving around the sun.
  3. Is an inertial frame because Newton's laws are applicable in this frame.
  4. Cannot be an inertial frame because the earth is rotating about its axis.
A particle is projected with velocity $v_{0}$ along $x-$ axis. A damping force is acting on the particle which is proportional to the square of the distance from the origin i.e., $ma =-\alpha x ^{2}.$ The distance at which the particle stops:
On which principle does the ball pen work?
Particle is dropped from the height of $20\,\,m$ from horizontal ground. There is wind blowing due to which horizontal acceleration of the particle becomes $6 ms^{^{-2}}$. Find the horizontal displacement of the particle till it reaches ground.  ........ $m$