MCQ
Angular width ($\beta$) of central maximum of a diffraction pattern on a single slit does not depend upon
- ✓Distance between slit and source
- BWavelength of light used
- CWidth of the slit
- DFrequency of light used
✓
Answer
Correct option: A.
Distance between slit and source
a
(a)For single slit diffraction pattern $d\sin \theta = \lambda $ ($d = $slit width)
Angular width = $2\theta = 2{\sin ^{ - 1}}\left( {\frac{\lambda }{d}} \right)$
It is independent of $D$ i.e. distance between screen and slit
(a)For single slit diffraction pattern $d\sin \theta = \lambda $ ($d = $slit width)
Angular width = $2\theta = 2{\sin ^{ - 1}}\left( {\frac{\lambda }{d}} \right)$
It is independent of $D$ i.e. distance between screen and slit
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
A convex lens of focal length f is placed somewhere in between an object and a screen. The distance between the object and the screen is x. If the numerical value of the magnification produced by the lens is m, then the focal length of the lens is
Consider the junction diode as ideal. The value of current flowing through $AB$ is
→Huygens' principle of secondary wavelets may be used to:
- Find the velocity of light in vacuum.
- Explain the particle behaviour of light.
- Find the new position of a wavefront.
- Explain Snell's law.
If energy of electron in ground state is $-13.6$ then find out speed of electron in fourth orbit of $H-$atom
→A sample contains 16 gm of a radioactive material, the half life of which is two days. After 32 days, the amount of radioactive material left in the sample is
If the energy of a photon corresponding to a wavelength of 6000 Å is $3.32 \times 10^{-19} \mathrm{J}$, the photon energy for a wavelength of 4000 Å will be
→A symmetric double convex lens is cut in two equal parts by a plane perpendicular to the principal axis. If the power of the original lens was $4D,$ the power of a cutlens will be :
→In the given network capacitance, $C_1=10\mu F, C_2 = 5\mu F$ and $C_=4\mu F$. What is the resultant capacitance between A and B
→The potential at a point, due to a positive charge of 100μC at a distance of 9m, is
Three capacitors of capacity $C_1,C_2,C_3$ are connected in series. Their total capacity will be
→