MCQ
Approximate atomic weight of an element is $26.89$. If its equivalent weight is $8.9$, the exact atomic weight of element would be
- A$26.89$
- B$8.9$
- C$17.8$
- ✓$26.7$
$ = 8.9 \times 3 = 26.7$ $\left( {{\rm{Valency}} = \frac{{{\rm{26}}{\rm{.89}}}}{{{\rm{8}}{\rm{.9}}}} \approx 3} \right)$.
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