MCQ
Area bounded by lines $y = 2 + x,$ $y = 2 - x$ and $x = 2$ is
  • A
    $3$
  • $4$
  • C
    $8$
  • D
    $16$

Answer

Correct option: B.
$4$
b
(b) Obviously, triangle $ACB$ is right angled at $C$.

$\therefore$ Required area $ = \frac{1}{2} \times AC \times BC$

$ = \frac{1}{2} \times 2\sqrt 2 \times 2\sqrt 2 = 4\,\, sq. \,unit$.

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