MCQ
$\int\frac{\text{x}^4+1}{\text{x}^2+1}\text{ dx}$ is equal to:
  • A
    $\frac{\text{x}^3}{3}+\text{x}+\tan^{-1}\text{x}+\text{c}$
  • B
    $\frac{\text{x}^3}{3}-\text{x}+\tan\text{x}+\text{c}$
  • C
    $\frac{\text{x}^3}{3}+\text{x}+2\tan^{-1}\text{x}+\text{c}$
  • $\frac{\text{x}^3}{3}-\text{x}+2\tan^{-1}\text{x}+\text{c}$

Answer

Correct option: D.
$\frac{\text{x}^3}{3}-\text{x}+2\tan^{-1}\text{x}+\text{c}$
$\frac{\text{x}^3}{3}-\text{x}+2\tan^{-1}\text{x}+\text{c}$

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