Arrange each set of compound in order of increasing boiling points.
Bromomethane, Bromoform, Chloromethane, Dibromomethane.
Bromomethane, Bromoform, Chloromethane, Dibromomethane.
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$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Br}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Br}\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \mid\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \mid\\\text{CH}_3-\text{Cl}\ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3-\text{Br}\ \ \ \ \ \ \ \ \ \text{CH}_2-\text{Br}\ \ \ \ \ \ \ \ \ \text{Br}-\text{CH}-\text{Br}\\\text{Chloromethane}\ \ \text{Bromoethane}\ \ \text{Dibromoethane}\ \ \text{Bromoform}$ For alkyl halides containing the same alkyl group, the boiling point increases with an increase in the atomic mass of the halogen atom. Since the atomic mass of Br is greater than that of Cl, the boiling point of bromomethane is higher than that of chloromethane. Further, for alkyl halides containing the same alkyl group, the boiling point increases with an increase in the number of halides. Therefore, the boiling point of Dibromomethane is higher than that of chloromethane and bromomethane, but lower than that of bromoform. Hence, the given set of compounds can be arranged in the order of their increasing boiling points as:Chloromethane < Bromomethane < Dibromomethane < Bromoform.
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