MCQ
Arrange the orbitals of $H-$ atom in the increasing order of their energy

$3p_x, 2s, 4d_{xy}, 3s, 4p_z, 3p_y, 4s$

  • A
    $2s < 3s < 3p_x = 3p_y < 4s < 4p_z < 4d_{xy}$
  • $2s < 3s = 3p_x = 3p_y < 4s = 4p_z = 4d_{xy}$
  • C
    $2s < 3s < 3p_x = 3p_y < 4s = 4p_z = 4d_{xy}$
  • D
    $2s < 3p_x = 3p_4 < 3s < 4s = 4p_z < 4d_{xy}$

Answer

Correct option: B.
$2s < 3s = 3p_x = 3p_y < 4s = 4p_z = 4d_{xy}$
b
In a single $e^-$ system energy of an orbital depends only upon value of $n$.

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