MCQ
Methylation of $10\, \mathrm{~g}$ of benzene gave $9.2\, \mathrm{~g}$ of toluene. Calculate the percentage yield of toluene $......$. (Nearest integer)
- A$75$
- ✓$78$
- C$81$
- D$96$
✓
Answer
Correct option: B.
$78$
b
Moles of $\mathrm{C}_{6} \mathrm{H}_{6}=10 / 78$
Moles of $\mathrm{C}_{6} \mathrm{H}_{6}=10 / 78$
moles of toluene $=10 / 78$
$\mathrm{w}_{\mathrm{t}}$ of toluene should be $=10 / 78 \times 92$
$\%$ yield $=\frac{9.2}{\frac{10}{78} \times 92} \times 100=78\, \%$
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