As in the figure, if a capacitor of capacitance $C$ is charged by connecting it with resistance $R$, then energy given by the battery will be
A$\frac{1}{2} C V^2$
BLess than $\frac{1}{2} C V^2$
C$CV ^2$
DMore than $CV ^2$
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C$CV ^2$
c (c)
$q=C V\left(1-e^{\frac{-t}{R C}}\right)$
$t=\infty \quad q=C V$
Battery gives $C V$ charge
$W=C V^2$
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