As shown in the figure a block of mass $10\,kg$ lying on a horizontal surface is pulled by a force $F$ acting at an angle $30^{\circ}$, with horizontal. For $\mu_{ s }=0.25$, the block will just start to move for the value of $F..........\,N$ : $\left[\right.$ Given $\left.g =10\,ms ^{-2}\right]$
JEE MAIN 2023, Medium
Download our app for free and get started
$N = Mg - F Sin 30^{\circ}$
$= mg -\frac{ F }{2}=100-\frac{ F }{2}=\frac{200- F }{2}$
$F Cos 30^{\circ}=\mu N$
$\sqrt{3} \frac{ F }{2}=0.25 \times\left(\frac{200- F }{2}\right)$
$4 \sqrt{3} F =200- F$
$F =\frac{200}{4 \sqrt{3}+1}=25.22$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1Acceleration of block $A$ varies with time as shown in figure the value of coefficient of kinetic friction between block $A$ and $B$ is the value of coefficient of kinetic friction between block $A$ and $B$ is ..............View Solution
- 2If force $F$ is increasing with time and at $t = 0 , F = 0$ where will slipping first start?View Solution
- 3A force $\vec{F}=\hat{i}+4 \hat{j}$ acts on the block shown. The force of friction acting on the block isView Solution
- 4A motorcycle is travelling on a curved track of radius $500\,m$. If the coefficient of friction between road and tyres is $0.5$, the speed avoiding skidding will be ....... $m/s$View Solution
- 5A given object takes $n$ times the time to slide down $45^{\circ}$ rough inclined plane as it takes the time to slide down an identical perfectly smooth $45^{\circ}$ inclined plane. The coefficient of kinetic friction between the object and the surface of inclined plane is :View Solution
- 6$A$ particle is moving in a circle :View Solution
- 7A block of mass $10\, kg$ is placed on an inclined plane. When the angle of inclination is $30°$, the block just begins to slide down the plane. The force of static friction is ....... $kg\, wt$View Solution
- 8A car is moving on a horizontal circular track of radius $0.2 \,km$ with a constant speed. If coefficient of friction between tyres of car and road is $0.45$, then speed of car may be ........ $m / s$ [Take $g=10 \,m / s ^2$ ]View Solution
- 9A particle has initial velocity $10\,\, m/s$. It moves due to constant retarding force along the line of velocity which produces a retardation of $5\,\, m/s^2$. ThenView Solution
- 10A box is lying on an inclined plane what is the coefficient of static friction if the box starts sliding when an angle of inclination is $60^o $View Solution