As shown in the figure, two infinitely long, identical wires are bent by $90^o$ and placed in such a way that the segments $LP$ and $QM$ are along the $x-$ axis, while segments $PS$ and $QN$ are parallel to the $y-$ axis. If $OP = OQ = 4\, cm$, and the magnitude of the magnetic field at $O$ is $10^{-4}\, T$, and the two wires carry equal current (see figure), the magnitude of the current in each wire and the direction of the magnetic field at $O$ will be $(\mu_ 0 = 4\pi \times10^{-7}\, NA^{-2})$
JEE MAIN 2019, Diffcult
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$B=2\left[\frac{\mu_{0} i}{4 n d}\left(\cos \theta_{1}-\cos \theta_{2}\right)\right]$
$B=10^{-4} \quad \theta_{1}=90^{\circ}$
$\mu_{0}=4 \pi \times 10^{-7} \quad \theta_{2}=180^{\circ}$
$d=4 \times 10^{-2}$
$\Rightarrow \mathrm{i}=20\, \mathrm{A}$ (into the page)
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