$(i)$ $PtCl _{4} . 5 NH _{3}$
$(ii)$ $PtCl _{4} . 4 NH _{3}$
$(iii)$ $PtCl _{4} . 3 NH _{3}$
$(iv)$ $PtCl _{4}. 2 NH _{3}$
ક્યા ક્રમને અનુસરે છે?
$\left[ Pt \left( NH _{3}\right)_{5} Cl \right] Cl _{3} \rightarrow\left[ Pt \left( NH _{3}\right)_{5} Cl \right]^{3+}+3 Cl ^{-}(4$ ions $)$
Reaction for $PtCl _{4} \cdot 4 NH _{3}$ is given as,
$\left[ Pt \left( NH _{3}\right)_{4} Cl _{2}\right] Cl _{2} \rightarrow\left[ Pt \left( NH _{3}\right)_{4} Cl _{2}\right]^{2+}+2 Cl ^{-}(3$ ions $)$
Reaction for $PtCl _{4} \cdot 3 NH _{3}$ is given as,
$\left[ Pt \left( NH _{3}\right)_{3} Cl _{3}\right] Cl \rightarrow\left[ Pt \left( NH _{3}\right)_{3} Cl _{3}\right]^{2+}+ Cl ^{-}(2 \text { ions })$
Reaction for $PtCl _{4} \cdot 2 NH _{3}$ is given as,
$\left[ Pt \left( NH _{3}\right)_{2} Cl _{4}\right]$ Non-ionic $(0$ ions $)$
$(1$ ફેરાડે $= 96500\, C,$ પરમાણ્વીય દળ of $Co = 59)$
$Fe_{(aq)}^{3 + } + {e^ - } \to Fe_{(aq)}^{2 + }$ ; ${E^o} = 0.771{\mkern 1mu} \,volts;{\mkern 1mu} $
${\mkern 1mu} {I_{2(g)}} + 2{e^ - } \to 2I_{(aq)}^ - \,;{\mkern 1mu} $ ${E^o} = 0.536{\mkern 1mu} \,volts$
કોષ પક્રિયા $2Fe^{3+}_{(aq)} + 2l^{-}_{(aq)} \rightarrow 2Fe^{2+}_{(aq)} + I_{2(g)}$ માટે $E^o_{cell} = ….$
$\lambda_{\mathrm{m}\left(\mathrm{H}_{2} \mathrm{SO}_{4}\right)}^{0}=\mathrm{x} \;\mathrm{S}\; \mathrm{cm}^{2} \mathrm{mol}^{-1}$
$\lambda_{\mathrm{m}\left(\mathrm{K}_{2} \mathrm{SO}_{4}\right)}^{0}=\mathrm{y} \;\mathrm{S\;cm}^{2} \mathrm{mol}^{-1}$
$\lambda_{\mathrm{m}(\mathrm{CH_3} \mathrm{COOK})}^{0}=\mathrm{z}\; \mathrm{S\;cm}^{2} \mathrm{mol}^{-1}$
$\mathrm{CH}_{3} \mathrm{COOH}$ માટે $\lambda_{\mathrm{m}}^{0}\left(\mathrm{in}\; \mathrm{S} \;\mathrm{cm}^{2} \mathrm{mol}^{-1}\right)$ શું હશે ?