Question
Assertion : 29 is the equivalent decimal number of binary number 11101.
Reason $\quad:(11101)=(1 \times 2+1 \times 2+1 \times 2+0 \times 2+1 \times 2)$.$=(16+8+4+0+1)=(29)$

Answer

(a) For detection of a particular wavelength $(\lambda)$ by a $P N$ photo diode, energy of incident light $>E \Rightarrow \frac{h c}{E_g}>\lambda$For $E_g=2.8 \mathrm{eV}, \frac{h c}{E_g}=\frac{6.6 \times 10^{-34} \times 3 \times 10^8}{2.8 \times 1.6 \times 10^{-19}}=441.9 \mathrm{~nm}$i.e. $\frac{h c}{E_g}<6000 \mathrm{~nm}$, so diode will not detect the wavelength of $6000 \ AA$.

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