$Assertion :$ A body that is good radiator is also a good absorber of radiation at a given wavelength.
$Reason :$ According to Kirchhoff’s law the absorptivity of a body is equal to its emissivity at a given wavelength.
AIIMS 2005, Easy
Download our app for free and get started
According to Kirchoff’s law
$\frac{{{e_\lambda }}}{{{e_\lambda }}} = {E_\lambda }$
Here, $E_{\lambda }$ is emissivity of black body which is constant, so, ${e_\lambda } \propto {a_\lambda }$ . It means good emitter are good absorber of radiation.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A black body at a temperature of $127°C$ radiates heat at the rate of $1 cal/cm^2 × sec$. At a temperature of $527°C$ the rate of heat radiation from the body in ($cal/cm^2 × sec$) will be
A copper rod $2\,m$ long has a circular cross-section of radius $1\, cm$. One end is kept at $100^o\,C$ and the other at $0^o\,C$ and the surface is covered by nonconducting material to check the heat losses through the surface. The thermal resistance of the bar in degree kelvin per watt is (Take thermal conductivity $K = 401\, W/m-K$ of copper):-
According to Newton’s law of cooling, the rate of cooling of a body is proportional to ${(\Delta \theta )^n}$, where $\Delta \theta $ is the difference of the temperature of the body and the surroundings, and n is equal to
A body cools in $7$ minutes from $60^{\circ}\,C$ to $40^{\circ}\,C$. The temperature of the surrounding is $10^{\circ}\,C$. The temperature of the body after the next $7$ minutes will be
A constant potential difference is applied to the ends of a graphite rod, whose resistance decreases with a rise of temperature. The rod can be $(1)$ covered with asbestos or $(2)$ left open to atmosphere. Answer for steady state.
The power radiated by a black body is $P$ and it radiates maximum energy at wavelength,$\lambda_0.$ If the temperature of the black body is now changed so that it radiates maximum energy at wavelength $\frac{3}{4}\lambda_0$, the power radiated by it becomes $nP$. The value of $n$ is
A slab consists of two parallel layers of two different materials of same thickness having thermal conductivities $K_1$ and $K_2$ . The equivalent conductivity of the combination is
Two thin metallic spherical shells of radii ${r}_{1}$ and ${r}_{2}$ $\left({r}_{1}<{r}_{2}\right)$ are placed with their centres coinciding. A material of thermal conductivity ${K}$ is filled in the space between the shells. The inner shell is maintained at temperature $\theta_{1}$ and the outer shell at temperature $\theta_{2}\left(\theta_{1}<\theta_{2}\right)$. The rate at which heat flows radially through the material is :-