MCQ
Assume each reaction is carried out in an open container. For which reaction will $\Delta H = \Delta E$ ?
  • $H_2(g) + Br_2(g) \to 2HBr(g)$
  • B
    $C(s) + 2H_2O(g) \to 2H_2(g) + CO_2(g)$
  • C
    $PCl_5(g) \to PCl_3(g) + Cl_2(g)$
  • D
    $2CO(g) + O_2(g) \to 2CO_2(g)$

Answer

Correct option: A.
$H_2(g) + Br_2(g) \to 2HBr(g)$
a
We know that, $\Delta H =\Delta U +\Delta PV$

But for a physical or chemical change, $\Delta H =\Delta U +\triangle ng\,RT$

where, $\triangle_{ n } g =$ No. of gaseous moles of product- Reactant

So, For $\Delta H =\Delta U$ or $\Delta H =\Delta E$

$\triangle ng$ has to $=0$

In $A$ option $\Delta ng =2-2=0$; Therefore, $\Delta H =\Delta E$.

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