MCQ
At $10^o C$ the value of the density of a fixed mass of an ideal gas divided by it pressure is $x.$ At  $110^o C$ this ratio is
  • A
    $\left( {\frac{{10}}{{110}}} \right)x$
  • $\;\left( {\frac{{283}}{{383}}} \right)x$
  • C
    $\;x$
  • D
    $\;\left( {\frac{{383}}{{283}}} \right)x$

Answer

Correct option: B.
$\;\left( {\frac{{283}}{{383}}} \right)x$
b
$Mass\, of\, the\,gas$ $=m$

At a fixed temperature and pressure, volume is fixed

Density of the gas $\rho=\frac{m}{V} \Rightarrow \frac{m}{V \cdot P}=\frac{m}{n R T}=x$

$x T=$ constant

At $10^{\circ} \mathrm{C}$ i.e., $283 \mathrm{K}, x T=x 283 \mathrm{K}$

At $110^{\circ} \mathrm{C}, x T=x^{\prime} 383 \mathrm{K}$

$\Rightarrow \quad x^{\prime}=\frac{283}{202} x$

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