MCQ
At what rate the potential difference between the plates of a capacitor be changed to set up a displacement current of $1\, A$ in a capacitor of $2\,\mu F$ ?
  • A
    ${10^{ + 6}}\,V/s$
  • $0.5 \times {10^{ + 6}}\,V/s$
  • C
    ${10^{ - 6}}\,V/s$
  • D
    $0.5 \times {10^{ - 6}}\,V/s$

Answer

Correct option: B.
$0.5 \times {10^{ + 6}}\,V/s$
b
$\mathrm{I}_{\mathrm{D}}=\frac{\mathrm{d} \mathrm{q}}{\mathrm{dt}}=\frac{\mathrm{d}}{\mathrm{dt}}(\mathrm{VC})=\mathrm{C} \frac{\mathrm{d} \mathrm{V}}{\mathrm{dt}}$

Here $\mathrm{I}_{\mathrm{p}}=1 \mathrm{\,A}, \mathrm{C}=2 \times 10^{-6} \mathrm{\,F}$

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