b
Escape velocity from the Earth's surface is
$v_{\text {escape }}=11200 \mathrm{ms}^{-1}$
Say at temperature $T,$ oxygen molecule attains escape velocity.
So, $v_{\text {escape }}=\sqrt{\frac{3 k_{B} T}{m_{\mathrm{O}_{2}}}} \Rightarrow 11200=\sqrt{\frac{3 \times 1.38 \times 10^{-23} \times T}{2.76 \times 10^{-26}}}$
On solving, $T=8.360 \times 10^{4} \mathrm{K}$