Question
Attempt this question on graph paper. Marks obtained by $200$ students in examination are given below:
Marks $0 - 10$ $10 - 20$ $20 - 30$ $30 - 40$ $40 - 50$ $50 - 60$ $60 - 70$ $70 - 80$ $80 - 90$ $90 - 100$
No. of students $5$ $10$ $14$ $21$ $25$ $34$ $36$ $27$ $16$ $12$
Draw an ogive for the given distribution taking $2$ cm $= 10$ makrs on one axis and $2\ cm = 20$ students on the other axis.
From the graph find:
(i) the median
(ii) the upper quartile
(iii) number of student scoring above $65$ marks.
(iv) If to students qualify for merit scholarship, find the minimum marks required to qualify.

Answer

Image

(i) Let A be the point on y-axis representing frequency
Here, n (no. of student) $= 200$ (even)
$\text { Median }=\left(\frac{ n }{2}\right)^{\text {th }} \text { term }$
$=\left(\frac{200}{2}\right)^{\text {th }} \text { term }$
$=100^{\text {th }} \text { term }$
From the graph $100$th term $= 57.5$
(ii) Upper quartile = $\frac{3 n}{4}$
$=\frac{3 \times 200^{\text {th }}}{4} \text { term }$
$=\frac{600}{4}=150^{\text {th }} \text { term }$
From graph $150^{th}$​​​​​​​ term
The upper quartile $= 72$
(iii) No. of students scoring above $65$ marks
$\Rightarrow$ Total No. of students - No. of students scoring $\leq 65$ marks
$\Rightarrow 200 - 126$
$\Rightarrow 74$ (approx.)
(iv) From the above diagram, we observe the students from $191$ to $200$ qualify for merit scholarship.
$\therefore$ The student who qualifies for merit scholarship scores more than $91$ marks.
$\therefore$ The minimum marks required to qualify for merit scholarship $= 92$ (approx.).

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