Average velocity of a particle executing $SHM$ in one complete vibration is
NEET 2019, Easy
Download our app for free and get started
Displacement $=$ zero in one complete oscillation
$\Rightarrow$ Average velocity $=\frac{\text { Dtsplacement }}{\mathrm{T}}=0$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1View SolutionThe graph shows the variation of displacement of a particle executing S.H.M. with time. We infer from this graph that
- 2The bob of a simple pendulum of mass m and total energy $E$ will have maximum linear momentum equal toView Solution
- 3A mass $M$ is suspended from a light spring. An additional mass m added displaces the spring further by a distance $x$. Now the combined mass will oscillate on the spring with periodView Solution
- 4Astone is swinging in a horizontal circle $0.8\, m$ in diameter at $30 \,rev / min.$ Adistant horizontal light beam causes a shadow of the stone to be formed on a nearly vertical wall. The amplitude and period of the simple harmonic motion for the shadow of the stone areView Solution
- 5Two bodies of masses $1\, kg$ and $4\, kg$ are connected to a vertical spring, as shown in the figure. The smaller mass executes simple harmonic motion of angular frequency $25\, rad/s$, and amplitude $1.6\, cm$ while the bigger mass remains stationary on the ground. The maximum force exerted by the system on the floor is ..... $N$ ( take $g = 10\, ms^{-2}$)View Solution
- 6View SolutionWhich of the following is a necessary and sufficient condition for S.H.M.
- 7View SolutionWhich of the following is a necessary and sufficient condition for S.H.M.
- 8A simple pendulum is set up in a trolley which moves to the right with an acceleration a on a horizontal plane. Then the thread of the pendulum in the mean position makes an angle $\theta $ with the verticalView Solution
- 9For a particle showing motion under the force $F=-5(x-2)$, the motion is ...........View Solution
- 10At time $t = 0$, a simple harmonic oscillator is at its extreme position. If it covers half of the amplitude distance in $1\, second$, then the time period of oscillation is ..... $s$View Solution