$\omega=\frac{30 \times 2 \pi}{60}=\pi$
or $\frac{2 \pi}{\mathrm{T}}=\pi$
$\therefore \mathrm{T}=2 \mathrm{sec}$
$x = a\,\sin \,\left( {\omega t + \pi /6} \right)$
After the elapse of what fraction of the time period the velocity of the particle will be equal to half of its maximum velocity?