\(n' = \left[ {\frac{{v + {v_O}}}{v}} \right]\,n\)
\( = \left[ {\frac{{v + v/5}}{v}} \right]\,n\)\( = \frac{6}{5}n = 1.2n\)
Increment in frequency \( = 0.2 n\)
so percentage change in frequency = \(\frac{{0.2n}}{n} \times 100= 20\%. \)
(જયાં $ {I_0} $ થ્રેશોલ્ડ તીવ્રતા)