Let equivalent resistance be \({r_{R,}}\)
then \(\frac{1}{{{r_R}}} = \frac{1}{r} + \frac{1}{r} + \frac{1}{r}\) ........... \(10\;{\rm{times}}\)
\(\therefore \frac{1}{{{r_R}}} = \frac{{10}}{r} = \frac{{10}}{{R/10}} = \frac{{100}}{R} \Rightarrow {r_R} = \frac{R}{{100}} = 0.01\,R\)