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Redox Reactions — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistryRedox Reactions2 Marks
Question
Balance the following equation:
$\text{Br}_2+\text{H}_2\text{O}_2\xrightarrow{ \ \ \ \ \ \ \ \ }\text{BrO}_3^-+\text{H}_2\text{O}$ (in acidic medium)
✓

Answer

$\text{H}_2\text{O}_2\xrightarrow{ \ \ \ \ \ \ \ }\text{H}_2\text{O}$ (Reduction half reaction)
$\text{H}_2\text{O}_2\xrightarrow{ \ \ \ \ \ \ }2\text{H}_2\text{O}$ (Balancing oxygen)
$2\text{H}^++\text{H}_2\text{O}_2\xrightarrow{ \ \ \ \ \ \ }2\text{H}_2\text{O}$ (Balancing hydrogen)
$2\text{e}^-+2\text{H}^++\text{H}_2\text{O}_2\xrightarrow{ \ \ \ \ \ \ }2\text{H}_2\text{O}$ (Balancing charge) ...(i)
$\text{Br}_2\xrightarrow{ \ \ \ \ \ \ }\text{BrO}_3^-$ (Oxidation half reaction)
$\text{Br}_2\xrightarrow{ \ \ \ \ \ \ }2\text{BrO}_3^-$ (Balancing bromine)
$6\text{H}_2\text{O}+\text{Br}_2\xrightarrow{ \ \ \ \ \ \ }2\text{BrO}_3^-$ (Balancing oxygen)
$6\text{H}_2\text{O}+\text{Br}_2\xrightarrow{ \ \ \ \ \ \ }2\text{BrO}_3^-+12\text{H}^+$ (Balancing hydrogen)
$6\text{H}_2\text{O}+\text{Br}_2\xrightarrow{ \ \ \ \ \ \ }2\text{BrO}_3^-+12\text{H}^++10\text{e}^-$ (Balancing charge) ...(ii)
Multiply equation (i) by 5 and the resultant to equation (ii).
$5\text{H}_2\text{O}_2+\text{Br}_2\xrightarrow{ \ \ \ \ \ \ \ \ \ }2\text{H}^++4\text{H}_2\text{O}+2\text{Br}\text{O}_3^-$

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