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Redox Reactions — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistryRedox Reactions3 Marks
Question
Balance the following equations by the oxidation number method.
$\text{Fe}^{2+}+\text{H}^++\text{Cr}_2\text{O}^{2-}_7\xrightarrow{ \ \ \ \ \ \ \ \ \ }\text{Cr}^{3+}+\text{Fe}^{3+}+\text{H}_2 \text{O}$
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Answer

$\text{Fe}^{2+}+\text{H}^{+}+\text{Cr}_2\text{O}^{2-}_7\xrightarrow{ \ \ \ \ \ \ \ \ }\text{Cr}^{3+}+\text{Fe}^{3+}+\text{H}_2\text{O}$$\stackrel{+2 \ \ \ \ \ \ \ }{\text{Fe}^{2+}}\text{H}^++\stackrel{+6}{\text{Cr}}_2\stackrel{-2 \ \ \ \ \ \ \ }{\text{O}^{2-}_7}\xrightarrow{ \ \ \ \ \ \ }\stackrel{+3 \ \ \ \ \ \ \ }{\text{Cr}^{3+}}+\stackrel{+3 \ \ \ \ \ \ \ \ \ }{\text{Fe}^{3+}}+\text{H}_2\text{O}$
  1. Balance the increase and decrease in O.N.
$6\stackrel{+2 \ \ \ \ \ \ \ }{\text{Fe}^{2+}}+\text{H}^++\stackrel{+6 \ \ \ }{\text{Cr}_2}\stackrel{-2 \ \ \ \ \ \ }{\text{O}^{2-}_7}\xrightarrow{ \ \ \ \ \ \ \ \ }2\stackrel{+3 \ \ \ \ \ \ }{\text{Cr}^{3+}}+6\stackrel{+3 \ \ \ \ \ \ \ }{\text{Fe}^{3+}}+\text{H}_2\text{O}$
  1. Balancing H and O atoms by adding $\text{H}^+$ and $\text{H}_2\text{O}$ molecules
$6\text{Fe}^{2+}+14\text{H}^++\text{Cr}_2\text{O}^{2-}_7\xrightarrow{ \ \ \ \ \ \ \ \ }2\text{Cr}^{3+}+6\text{Fe}^{3+}+7\text{H}_2\text{O}$

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